The position of a car traveling between two stop signs aiong a straight city block is given by r=(9t−(245) sin (52t))m
Posted: Thu Jul 14, 2022 2:46 pm
The position of a car traveling between two stop signs aiong a straight city block is given by r=(9t−(245) sin (52t))m, where t denotes time (in seconds) and where the argument of the sine function is measured in radians. Compute the displacement of the car between 2.59 s and 3.7 s, as well as between 11.1 and 12.7 s. For each of these time intervals compute the average velocity. The displacement of the car between 2.59 and 3.7 s is u^r m. (Round the final answer to four decimal places.) The displacement of the car between 11.1 and 127 s is u^r. (Round the final answer to two decimal places.) The average velocity of the car between 2.59 and 3.7 s is u^r m/s. (Round the final answer to four decimal places) The average velocity of the car between 11.1 and 12.7 s is u^pm/s. (Round the final answer to three decimal places.)