The position of a car traveling between two stop signs aiong a straight city block is given by r=(9t−(245​) sin (52t​))m

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The Position Of A Car Traveling Between Two Stop Signs Aiong A Straight City Block Is Given By R 9t 245 Sin 52t M 1 (23.21 KiB) Viewed 46 times

The position of a car traveling between two stop signs aiong a straight city block is given by r=(9t−(245​) sin (52t​))m, where t denotes time (in seconds) and where the argument of the sine function is measured in radians. Compute the displacement of the car between 2.59 s and 3.7 s, as well as between 11.1 and 12.7 s. For each of these time intervals compute the average velocity. The displacement of the car between 2.59 and 3.7 s is u^r​ m. (Round the final answer to four decimal places.) The displacement of the car between 11.1 and 127 s is u^r​. (Round the final answer to two decimal places.) The average velocity of the car between 2.59 and 3.7 s is u^r​ m/s. (Round the final answer to four decimal places) The average velocity of the car between 11.1 and 12.7 s is u^p​m/s. (Round the final answer to three decimal places.)