Answer Happy

Posted: **Thu Jul 14, 2022 2:44 pm**

: Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 1 (32.79 KiB) Viewed 45 times

: Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 2 (32.79 KiB) Viewed 45 times

: Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 3 (47.7 KiB) Viewed 45 times

: Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 4 (36.2 KiB) Viewed 45 times

Problem 1: Use vector loop equation to find (a) the angular accelerations and their directions (CCW or CW) of links 3 and 4 and (b) accelerations of points A,B and P of the fourbar linkage given in Problem 1 of HW#7. Use ω2=12rad/s and α2=−5rad/s2. Use the results of Prob. 1 of HW#7 and solve the problem for the open solution (position shown below). All dimensions are in inches.
Problem 1: Use vector loop equation to find (a) the angular velocities and their directions (CCW or CW) of links 3 and 4, (b) velocities of points A,B and P and (c) mechanical advantage of the fourbar linkage given in Problem 1 of HW #3 at the position shown. Use ω2=12rad/s. Use the results of Prob. 1 of HW #3 and solve the problem for the open solution (position shown below). All dimensions are in inches.
problen I (cont'd) VB=−0.7860∘−0.718j∘ in/s VP=VA+VPA VPA=R˙PA=−pω3s(θ3+δ3)i+pω3C(θ3+δ3)j VPA=−0.97(−13.13)S(23.3+54)i+0.97(−113.13)C(23.3+50) VPA=12.42i−2.80j in /s VP=−4.32i+7.48i+12.42j−2.83j VP=8.10i+4.68j in 1/ (c) mv=wout win (rout rin )=ω4L4w2L2 rin =L2,rout t=Ly uv=1.25(0.85)12(0.72)=8.13