Problem 1: Use vector loop equation to find (a) the angular accelerations and their directions (CCW or CW) of links 3 an

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Problem 1: Use vector loop equation to find (a) the angular accelerations and their directions (CCW or CW) of links 3 an

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Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 1
Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 1 (32.79 KiB) Viewed 44 times
Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 2
Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 2 (32.79 KiB) Viewed 44 times
Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 3
Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 3 (47.7 KiB) Viewed 44 times
Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 4
Problem 1 Use Vector Loop Equation To Find A The Angular Accelerations And Their Directions Ccw Or Cw Of Links 3 An 4 (36.2 KiB) Viewed 44 times
Problem 1: Use vector loop equation to find (a) the angular accelerations and their directions (CCW or CW) of links 3 and 4 and (b) accelerations of points A,B and P of the fourbar linkage given in Problem 1 of HW#7. Use ω2​=12rad/s and α2​=−5rad/s2. Use the results of Prob. 1 of HW#7 and solve the problem for the open solution (position shown below). All dimensions are in inches.
Problem 1: Use vector loop equation to find (a) the angular velocities and their directions (CCW or CW) of links 3 and 4, (b) velocities of points A,B and P and (c) mechanical advantage of the fourbar linkage given in Problem 1 of HW #3 at the position shown. Use ω2​=12rad/s. Use the results of Prob. 1 of HW #3 and solve the problem for the open solution (position shown below). All dimensions are in inches.
problen I (cont'd) VB​=−0.7860∘−0.718j∘ in/s VP​=VA​+VPA​ VPA​=R˙PA​=−pω3​s(θ3​+δ3​)i+pω3​C(θ3​+δ3​)j VPA​=−0.97(−13.13)S(23.3+54)i+0.97(−113.13)C(23.3+50) VPA​=12.42i−2.80j in /s VP​=−4.32i+7.48i+12.42j−2.83j VP​=8.10i+4.68j in 1/ (c) mv​=wout ​win ​​(rout ​rin ​​)=ω4​L4​w2​L2​​ rin ​=L2​,rout ​t=Ly​ uv​=1.25(0.85)12(0.72)​=8.13
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