Problem 3: Belon Gets Ready for Interplanetary Name Dropping Belon is going "name drop" on many planets, and needs to ca

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answerhappygod
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Problem 3: Belon Gets Ready for Interplanetary Name Dropping Belon is going "name drop" on many planets, and needs to ca

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Problem 3 Belon Gets Ready For Interplanetary Name Dropping Belon Is Going Name Drop On Many Planets And Needs To Ca 1
Problem 3 Belon Gets Ready For Interplanetary Name Dropping Belon Is Going Name Drop On Many Planets And Needs To Ca 1 (119.88 KiB) Viewed 21 times
Problem 3 Belon Gets Ready For Interplanetary Name Dropping Belon Is Going Name Drop On Many Planets And Needs To Ca 2
Problem 3 Belon Gets Ready For Interplanetary Name Dropping Belon Is Going Name Drop On Many Planets And Needs To Ca 2 (101.2 KiB) Viewed 21 times
Problem 3 Belon Gets Ready For Interplanetary Name Dropping Belon Is Going Name Drop On Many Planets And Needs To Ca 3
Problem 3 Belon Gets Ready For Interplanetary Name Dropping Belon Is Going Name Drop On Many Planets And Needs To Ca 3 (63.77 KiB) Viewed 21 times
Octave or MATLAB please
Problem 3: Belon Gets Ready for Interplanetary Name Dropping Belon is going "name drop" on many planets, and needs to calculate how long it will take to "drop" specific target distances under different atmospheric constraints. Function Declaration: function (timeNoFrict, timelinearFrict, timequadFrict] = belonDropſk, targetdistance) Similar to Hahn 14.3 in older Editions, 12.3 in 6th edition Write a function that builds upon the script in "Dynamical Systems: Free Fall" for the free-fall problem. Specifications / Requirements: Improvements and Modifications: • Provide no plotting. • Provide no display output. • Inputs include: k = air friction coefficient o target Distance = the distance for which the "time" is to be determined • Return three different values of time. in seconds, at which the object reaches the target distance. • See the function declaration for details on return values. Submit your function.
% Friction coefficient provided in the problem statement. k - 0.2: % Acceleration of gravity in m/s/s. g - 9.81; % % Step 2: Selection of time steps for computing solutions % .01: % % Step 3: Set initial condition (the same for all cases) % t(1) = 0.; V(1) = 0.; y(1) = 0.; % t - 0:dt:5: dt % Step 4: Compute exact solutions at each time step % from t = 0 to 5. % % (a) Without friction: % v-g* t; y-g* t. 2 * 0.5; 品中心 % (b) Linear friction ee velf = (g/k) * (1. - exp(-k*t)); yelf = (g/k) * t - (g/(k*2)) * (1.-exp(-k*t)); % % (c) Quadratic friction % veqf = sqrt(g/k) * tanh( sqrt(g*k) * t); yeqf = (1/k) * log(cosh( sqrt(g*k) * t)); % % Step 5: Computation of the terminal speeds % (cases with friction) 心中
Step 6: Graphical comparison plot(t.y.t.yelf.t.yeqf) title('Fig 1. Comparison of results) xlabel' Time. t') ylabel' Distance, y) 14.3 Free Fall % figure plot(t,v.t.velf.t.veqf) title('Fig. 2. Comparison of results) xlabel(" Time, t') ylabel("Speed. v) % Step 7: Comparison of distance and speed at t - 5 disp(' '); fprintf(y(t) - %f. yelf(t) - %f. yeqf(t) - f at t - f\n'.... y(501).yelf(501).yeqf (501).t(501)) disp(' '); fprintf(" v(t) - %f, velf(t) - %f. veqf(t) - %f at t - %f\n'.... y(501).yelf(501),yeqf(501).t(501)) % * Step 8: Comparison of terminal velocity % disp(' '); fprintf(" velft - %f, veqft - 3f\n'.... velft.veqft) % % Step 9: Stop %
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