3. Use the rules of inference to show the argument below is valid. p∧qp→(r∧q)r→(s∨t)∼s∴t
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3. Use the rules of inference to show the argument below is valid. p∧qp→(r∧q)r→(s∨t)∼s∴t
3. Use the rules of inference to show the argument below is valid. p∧qp→(r∧q)r→(s∨t)∼s∴t
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