2 The cylinder of mass m is to be supported by the two centially vertical A-35 steel wires each has a cross-sectional ar

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2 The Cylinder Of Mass M Is To Be Supported By The Two Centially Vertical A 35 Steel Wires Each Has A Cross Sectional Ar 1 (40.26 KiB) Viewed 28 times

2 The cylinder of mass m is to be supported by the two centially vertical A-35 steel wires each has a cross-sectional area of 20 mm. Knowing that allowable normal stress of the steel L ISO MPa and the elongation of the cable must not exceed 1 mm. find the maximum mass of the sylinder that can be carried by the system (Ex=2000&Pag-10 min +1 Fy=0; FAB+ Fre - W=0 @ W=@ AC 4:20 1500 • A-20.00 FAB 8 8. AD 3 AC 1500 Fac 1000 EA 5 1-5 FAB=FAC 2 2 F AB = 0.4 W; FAC = 0.6W (FAC > FAB FAC is critical TACT 150 = FAC TAL = 3000 M (3) A wung Torow = 150 RO 8 Facil TAC 1000 1 FACT = 4000N 3 allow EA 200, do X20 FAE 3000 is critical TAC = 0.6 We obmy ② 3000 = 0.6 x mx 10 m=500 kg ©