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132kV 11kV 3.3kV E D C B 1 1 1 1 15,000 Meters 210mm Overhead Line 6.202 2.000 Meters 2407? Cable 0.2422 200 Meters 120m

Posted: Tue Apr 26, 2022 2:55 pm
by answerhappygod
132kv 11kv 3 3kv E D C B 1 1 1 1 15 000 Meters 210mm Overhead Line 6 202 2 000 Meters 2407 Cable 0 2422 200 Meters 120m 1
132kv 11kv 3 3kv E D C B 1 1 1 1 15 000 Meters 210mm Overhead Line 6 202 2 000 Meters 2407 Cable 0 2422 200 Meters 120m 1 (362.19 KiB) Viewed 37 times
132kv 11kv 3 3kv E D C B 1 1 1 1 15 000 Meters 210mm Overhead Line 6 202 2 000 Meters 2407 Cable 0 2422 200 Meters 120m 2
132kv 11kv 3 3kv E D C B 1 1 1 1 15 000 Meters 210mm Overhead Line 6 202 2 000 Meters 2407 Cable 0 2422 200 Meters 120m 2 (82.64 KiB) Viewed 37 times
How did we get the t which is 0.01?
132kV 11kV 3.3kV E D C B 1 1 1 1 15,000 Meters 210mm Overhead Line 6.202 2.000 Meters 2407? Cable 0.2422 200 Meters 120mm? Cable Fuses Type gG F 200A 132kV 0.0492 10MVA 0.29% R, CT, RCTI 1 A Rg CTT -XIAO 150/14 R2 CT XTTXT O 7500/54 250/5A If1 500/14 Source If5 If4 If3 If2 F: 150A Relays Plug Setting 30MVA 132/11kV 22.5% 4MVA 11/3.36V 7% Figure 1: Challenge Problem - Radial Network Diagram
Substation A Base Current Sbase I base 13 x V base 10x106 I base = = 1749.55 A V3 x 3.3x103 10x106 F.L = = 35.77 MVA 0.175+0.075+0.0033+0.0198+0.0036+0.0029 Fault Level Fault Current at 3.3KV Sbase F. L = Ztotal F.L If = V3 x Vbase I base le = X2 35.77 IF = 6258.13 A V3 x 3.3 1749.55 If = = 6257.33 A 0.2796 Fault Current at 3.3KV Fault Current at 11KV If = 6257.33x0.3 = 1877.2 A Pickup Current at 3.3KV 100 Ipickup = 250x = 250 A 100 3.3 lg = lfx 11 Ipickup PS% = x100 CTprimary IF PSM = Ipickup t = 0.4xt + 0.5 Plug Setting Multiplier (PSM) Operating Time 1877.2 PSM = = 7.5 250 t = 0.4x0.01 + 0.5 = 0.154 sec Time Multiplier Setting (TMS) PSM2 – 1 TMS = -xt 80 7.52 – 1 TMS = -x0.154 = 0.11 80