Find the inverse Laplace transform for the function X(s) = \(\frac{2s-1}{s^2+4s+8}\).

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answerhappygod
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Find the inverse Laplace transform for the function X(s) = \(\frac{2s-1}{s^2+4s+8}\).

Post by answerhappygod »

a) e-2t cos⁡2t u(t) – e-2t sin⁡2t u(t)
b) 2e-2t cos⁡2t u(t) – \(\frac{5}{2}\) e-2t sin⁡2t u(t)
c) 2e-2t cos⁡2t u(t) – e-2t sin⁡2t u(t)
d) e-2t cos⁡2t u(t) – \(\frac{5}{2}\) e-2t sin⁡2t u(t)
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