A Rigid Bar Abcd Is Supported By A Pin Connection At A And By Two Axial Bars 1 And 2 Bar 1 Is A 30 In Long Br 1 (66.64 KiB) Viewed 33 times
a = - Rigid bar ABCD is supported by a pin connection at A and by two axial bars (1) and (2). Bar (1) is a 30-in-long bronze [E = 14200 ksi, 8.5 x 10-6/°F] bar with a cross-sectional area of 1.75 in.2. Bar (2) is a 48-in.-long aluminum alloy [E = 8900 ksi, a = 11.8 x 106/°F] bar with a cross-sectional area of 2.25 in.2. Both bars are unstressed before the load Pis applied. Assume L1=30 in., L2=48 in., a=38 in., b=46 in., and c=18 in. If a concentrated load of P= 25 kips is applied to the rigid bar at D and the temperature is decreased by 80°F, determine: (a) the normal stresses in bars (1) and (2). (b) the normal strains in bars (1) and (2). (c) the deflection of the rigid bar at point D. (2) L2 A B с D L Р a b Using a FBD of the beam, assuming members in tension, relate the force in the members and the applied force P by summing moments about the pin at A. Assume counterclockwise is positive in writing the equation.
Relate the deformations of member (1) and member (2). Answer: 8 = i 0.452 82. Save for Later Attempts: 1 of 3 used Submit Answer Part 4 Using the relationships for deformation in terms of force and temperature change for each member together with Eqn. (3), derive a compatibility equation for the structure. [F2L2 FL Answer: +0,47 L A E i + a24T2L2 [A₂E₂ Save for Later Attempts: 0 of 3 used Submit Answer
Part 5 Solve for F2 and F1 using the results from parts 1 and 4. Answers: F1 = i kips, F2= i kips. Save for Later Attempts: 0 of 3 used Submit Answer Part 6 * Incorrect Each member is an axial force member subject to an axial load. Determine the normal stress in each bar. Use positive if tensile, negative if compressive. Answers: 6 = i 26.1673 ksi, 02 i 22.6991 ksi. Save for Later Attempts: 1 of 3 used Submit Answer
Part 7 X Incorrect The normal strain includes a force component and a thermal component. Determine the normal strain in bars (1) and (2). Use positive if tensile, negative if compressive. Answers: €) = i - 1166.67 με, έ: = i 1604.16 με. Save for Later Attempts: 1 of 3 used Submit Answer
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