What will be the equation of normal to the hyperbola 3x2 – 4y2 = 12 at the point (x1, y1)?

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answerhappygod
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What will be the equation of normal to the hyperbola 3x2 – 4y2 = 12 at the point (x1, y1)?

Post by answerhappygod »

a) 3x1y + 4y1x + 7x1y1 = 0
b) 3x1y + 4y1x – 7x1y1 = 0
c) 3x1y – 4y1x – 7x1y1 = 0
d) 3x1y – 4y1x + 7x1y1 = 0
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