Find the cartesian equation of the line which is passing through the point (5,-6,1) and parallel to the vector \(5\hat{i

[answerhappygod]

a) \(\frac{x-5}{5}=\frac{y-4}{6}=\frac{z+1}{-3}\)
b) \(\frac{x-5}{5}=\frac{z+6}{2}=\frac{y-1}{3}\)
c) \(\frac{x+5}{4}=\frac{y-8}{2}=\frac{z-1}{-3}\)
d) \(\frac{x-5}{5}=\frac{y+6}{2}=\frac{z-1}{-3}\)