a) –\(tan^{-1}\frac{x}{4}+C\)
b) \(\frac{1}{2} tan^{-1}\frac{x}{2}+C\)
c) \(\frac{3}{4} tan^{-1}x+C\)
d) \(\frac{3}{4} tan^{-1}\frac{3x}{2}+C\)
Find \(\int \frac{dx}{x^2+4}\).
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answerhappygod
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Find \(\int \frac{dx}{x^2+4}\).
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