a) \(\frac{1}{2} tan^{-1}\frac{x^2-8x}{2}+C\)
b) \(\frac{5}{2} tan^{-1}\frac{x-4}{2}+C\)
c) \(\frac{1}{2} tan^{-1}\frac{x-4}{2}+C\)
d) \(x-\frac{1}{2} tan^{-1}\frac{x-4}{2}+C\)
Find \(\int \frac{dx}{x^2-8x+20}\).
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answerhappygod
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Find \(\int \frac{dx}{x^2-8x+20}\).
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