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Posted: **Tue Jul 12, 2022 1:02 pm**

: Chem 103hw 1 2pcl3 O2 2pocl3 119 3491 34 A Moles Pcl3 B Moles O2 C Moles Pocl3 Based On Pcl3 D Moles Po 1 (45.44 KiB) Viewed 34 times

Chem 103HW (1) 2PCl3+O2→2POCl3 119+3491.34 a) moles PCl3= b) moles O2= c) moles POCl3 based on PCl3= d) moles POCl3 based on O2= e) mass of POCl3= given: the actual yield is 11.2 g of POCl3 f) what is the percent yield?

Answer Happy

Chem 103HW (1) 2PCl3​+O2​→2POCl3​ 119+3491.34​ a) moles PCl3​= b) moles O2​= c) moles POCl3​ based on PCl3​= d) moles PO

Chem 103HW (1) 2PCl3​+O2​→2POCl3​ 119+3491.34​ a) moles PCl3​= b) moles O2​= c) moles POCl3​ based on PCl3​= d) moles PO

Chem 103HW (1) 2PCl3+O2→2POCl3 119+3491.34 a) moles PCl3= b) moles O2= c) moles POCl3 based on PCl3= d) moles PO

Chem 103HW (1) 2PCl3+O2→2POCl3 119+3491.34 a) moles PCl3= b) moles O2= c) moles POCl3 based on PCl3= d) moles PO