- Chem 103hw 1 2pcl3 O2 2pocl3 119 3491 34 A Moles Pcl3 B Moles O2 C Moles Pocl3 Based On Pcl3 D Moles Po 1 (45.44 KiB) Viewed 33 times
Chem 103HW (1) 2PCl3+O2→2POCl3 119+3491.34 a) moles PCl3= b) moles O2= c) moles POCl3 based on PCl3= d) moles PO
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Chem 103HW (1) 2PCl3+O2→2POCl3 119+3491.34 a) moles PCl3= b) moles O2= c) moles POCl3 based on PCl3= d) moles PO
Chem 103HW (1) 2PCl3+O2→2POCl3 119+3491.34 a) moles PCl3= b) moles O2= c) moles POCl3 based on PCl3= d) moles POCl3 based on O2= e) mass of POCl3= given: the actual yield is 11.2 g of POCl3 f) what is the percent yield?
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