N₂ (8) + 3 H₂ (8)2NH3 (8) For the above reaction, K = 7.0 x 103 M2. If a current mixture contains [N₂] = 0.01 M. [H₂] =

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N 8 3 H 8 2nh3 8 For The Above Reaction K 7 0 X 103 M2 If A Current Mixture Contains N 0 01 M H 1 (20.7 KiB) Viewed 36 times

N₂ (8) + 3 H₂ (8)2NH3 (8) For the above reaction, K = 7.0 x 103 M2. If a current mixture contains [N₂] = 0.01 M. [H₂] = 0.025 M and [NH3] = 0.033 M, is this reaction at equilibrium? If not, which way must the equilibrium shift in order to reach equilibrium? Reaction must shift towards products O Reaction is at equilibrium O Reaction must shift towards reactants