(15 points) 4. Unpolarized light of intensity 65. W/m² is incident on a stack of two ideal polarizers. The light that is

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(15 points) 4. Unpolarized light of intensity 65. W/m² is incident on a stack of two ideal polarizers. The light that is

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15 Points 4 Unpolarized Light Of Intensity 65 W M Is Incident On A Stack Of Two Ideal Polarizers The Light That Is 1
15 Points 4 Unpolarized Light Of Intensity 65 W M Is Incident On A Stack Of Two Ideal Polarizers The Light That Is 1 (33.07 KiB) Viewed 49 times
(15 points) 4. Unpolarized light of intensity 65. W/m² is incident on a stack of two ideal polarizers. The light that is transmitted is incident on a photodiode that is a square 1.0-cm on a side. This photodiode absorbs 10. mJ in 4.0 s of exposure time. Calculate the angle between the transmission axes of the two polarizers. 10-Point Bonus: For the set up in P4 above, the photodiode is 15% efficient, and has an output voltage of 2.1 V. If the angle, 0, between the transmission axes of the polarizers is varied, determine an expression for the output current of the photodiode in terms of the angle 0.
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