Solve the IVP using Taylor's series(3rd deg polynomial). dy/dx = 3x2y; y(1)=1 y'(1) = y"(1) |y(1)= y(1.4) = (2 decimal p
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Solve the IVP using Taylor's series(3rd deg polynomial). dy/dx = 3x2y; y(1)=1 y'(1) = y"(1) |y(1)= y(1.4) = (2 decimal p
Solve the IVP using Taylor's series(3rd deg polynomial). dy/dx = 3x2y; y(1)=1 y'(1) = y"(1) |y(1)= y(1.4) = (2 decimal places) True value at x=1.4 (2 decimal places)
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