You may need to use the appropriate technology to answer this question. The following data are from a completely randomized design. Sample mean Sample variance A 161 Source of Variation 143 Treatments 166 Error 144 Total 148 174 156 Treatment B 141 155 124 143 135 Sum of Squares 154 142 с 127 122 138 141 (a) Compute the sum of squares between treatments. 151 (b) Compute the mean square between treatments. 125 (c) Compute the sum of squares due to error. 134 165.2 137.6 125.6 (d) Compute the mean square due to error. (Round your answer to two decimal places.) (e) Set up the ANOVA table for this problem. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Degrees of Freedom Mean Square F p-value
(f) At the α = 0.05 level of significance, test whether the means for the three treatments are equal. State the null and alternative hypotheses. оно: на = μB = MC Ha: MA MB MC Ho: MA = MB = MC Ha: Not all the population means are equal. Ho: Not all the population means are equal. Ha: MA = MB = MC Ho: MA MB MC # # H₂: MA= MB = MC O Ho: At least two of the population means are equal. Ha: At least two of the population means are different. Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. O Do not reject Ho. There is sufficient evidence to conclude that the means for the three treatments are not equal. O Reject Ho. There is not sufficient evidence to conclude that the means for the three treatments are not equal. O Reject Ho. There is sufficient evidence to conclude that the means for the three treatments are not equal. O Do not reject Ho. There is not sufficient evidence to conclude that the means for the three treatments are not equal.
You may need to use the appropriate technology to answer this question. The following data are from a completely randomi
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You may need to use the appropriate technology to answer this question. The following data are from a completely randomi
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