I Section (III) 0.8 b 0.8 b b Section (II) Fig. 1-b Section (1) Figure (1) 2 m 3 m 6kN/m Fig. 1-a 3 KN 1m 2 m 00 For the

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answerhappygod
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I Section (III) 0.8 b 0.8 b b Section (II) Fig. 1-b Section (1) Figure (1) 2 m 3 m 6kN/m Fig. 1-a 3 KN 1m 2 m 00 For the

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I Section Iii 0 8 B 0 8 B B Section Ii Fig 1 B Section 1 Figure 1 2 M 3 M 6kn M Fig 1 A 3 Kn 1m 2 M 00 For The 1
I Section Iii 0 8 B 0 8 B B Section Ii Fig 1 B Section 1 Figure 1 2 M 3 M 6kn M Fig 1 A 3 Kn 1m 2 M 00 For The 1 (54.98 KiB) Viewed 38 times
I Section (III) 0.8 b 0.8 b b Section (II) Fig. 1-b Section (1) Figure (1) 2 m 3 m 6kN/m Fig. 1-a 3 KN 1m 2 m 00 For the shown steel loaded simply supported beam in Figure (1) get the following: 1. Beam reactions and bending moment diagram. Identify the value and the position of the maximum bending value in (N.mm). 2. Design the given steel loaded simply supported beam (Fig. 1-a) on static flexural stress by getting the suitable cross-section of the following three cross-section profiles (Fig. 1-b): (a) Solid square section (I), (b) Box square section (II) and (c) Standard I-beam section (III) in both x-x and y-y orientations. 3. Get the factor of safety (n) for each standard cross-section. 4. If each 1 kg of the used structural steel (steel density 7.8 g/cm³) beam costs 20 SAR calculate the cost of each designed cross-section beam and show how much did you save in SAR by selecting the lighter cross-section profile and/or orientation? (Use design factor (na) = 3 and material's yield strength =390 MPa)
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