Question 10 1 Point Saved Impulse Fdt Momentum Mv Mv Fdt Mv Rxm Rw Rxfdt R M W Mdt R M W Iwl Mdt Iw2 1 (134.82 KiB) Viewed 23 times
PLease take your time and make sure the answer is correct.You might have seen a similar problem already on answers. DO NOT copyit thinking it is right as it contains different values anddimensions. Question 10 (1 point) ✔ Saved Impulse (Fdt) → momentum (mv) mv + Fdt mv rXm(rw) +rXFdt r²m w + Mdt r²m w Iwl + Mdt = Iw2 - rXm (rw) = T A small grinding wheel is attached to the shaft of an electric motor which has a rated speed of 4,075 rpm. When the power is turned off, the unit coasts to rest in 44 sec. The grinding wheel and rotor have a combined mass of 6.0 kg and a combined radius of gyration about its mass center of 43 mm. Determine the average magnitude of the couple, M, due to kinetic friction in the bearings of the motor. Your Answer: 50
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