A gas undergoes a process from state 1, where p1 = 60 psi, v1 = 6.0 ft3/lb, to state 2 where p2 = 20 psi, according to p

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A gas undergoes a process from state 1, where p1 = 60 psi, v1 =6.0 ft3/lb, to state 2 where p2 = 20 psi, according to pv1.3 =constant. The relationship between pressure, specific volume, andinternal energy is u = 0.2651 pv – 95.436, where p is in psi, v isin ft3/lb, and u is in Btu/lb. The mass of gas is 10 lb. Neglectingkinetic and potential energy effects, determine the heat transfer,in Btu. Ans: 283.6 Btu.

A Gas Undergoes A Process From State 1 Where P1 60 Psi V1 6 0 Ft3 Lb To State 2 Where P2 20 Psi According To P 1 (88.55 KiB) Viewed 55 times

5. A gas undergoes a process from state 1, where p₁ = 60 psi, v₁ = 6.0 ft³/lb, to state 2 where p2 = 20 psi, according to pu¹.3 = constant. The relationship between pressure, specific volume, and internal energy is u = 0.2651 pv - 95.436 where p is in psi, u is in ft³/lb, and u is in Btu/lb. The mass of gas is 10 lb. Neglecting kinetic and potential energy effects, determine the heat transfer, in Btu. Ans: 283.6 Btu