H: Multiple Subsystems - Block on Table w Hanging Blocks Bookmark this page You have a frictionless table, three blocks

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H Multiple Subsystems Block On Table W Hanging Blocks Bookmark This Page You Have A Frictionless Table Three Blocks 1 (31.48 KiB) Viewed 79 times

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H Multiple Subsystems Block On Table W Hanging Blocks Bookmark This Page You Have A Frictionless Table Three Blocks 3 (20.92 KiB) Viewed 79 times

H: Multiple Subsystems - Block on Table w Hanging Blocks Bookmark this page You have a frictionless table, three blocks of masses m₁. m₂, and m3, two frictionless pulleys, and ideal rope. Place m₂ on the table, and use the two pieces of ideal rope and the two pulleys to hang masses my and me from the left and right on the table, respectively.. Take my > m₁. The tensions in the left and right pieces of ideal rope are 73 and 7₁ respectively. The acceleration of gravity is given by g Before starting choose a coordinate axis positive in the direction of the motion. This choice means the positive direction of motion for the left block is up, while the positive direction of motion of the right block is down. Draw a physical diagram. As you proceed, draw three free body diagrams, one for each block.
Solve the three Newton's Second Law equations for the tensions T and T₁. Enter responses using m1 for m₁. m 2 for m₂. m3 for ms. g for g. F.(G1) for FG1. and F(G3) for FG3 T₁=((2 m 3+m_2) F (G1))/(m_1+m_2+m_3) (2-m3 + m₂). FG₁ m₂ + m₂ + my T3 ((2 m_1+m_2)+F (G3))/(m_1+m_2+m_3) (2-mi + m₂) FG3 m₂ + m₂ + m3 SUBMIT You have used 2 of 10 attempts Creating Atwood's Machine 0.0/10.0 points (graded) ✓ ✓ T₁= 6 Save As a special case and a check, set the mass on the table to zero to create the equivalent of Atwood's machine. The tensions in this case now represent the tension in the one piece of rope connecting the hanging masses and should have the same value. 0 Show Answer Verify the tensions do indeed become the same when m₂=0 by expressing them in terms of mass one, mass three, and the acceleration of gravity. Enter responses using m1 for m₁, m 2 for m₂, m3 for m3. g for g. F (G1) for Fa. and F.(G3) for Fox T₁ x
Atwood's Machine in Equilibrium 0.0/10.0 points (graded) Another special case and a check occurs when you both set the mass on the table to zero and set my mg. The tensions in this case are now the forces needed to keep the hanging masses from accelerating. Express the tensions when m₂=0 in terms of m, where my mms, and the acceleration of gravity, and notice each is the expected result. Enter responses using m for m, and g for g. Ti Ts SUBMIT You have used 0 of 10 attempts