The horizontal rigid beam ABCD is supported by vertical bars BE
and CF and is loaded by vertical forces P1 = 400 kN and P2 = 360 kN
acting at points A and D, respectively (see figure). Bars BE and CF
are made of steel (E = 200 GPa) and have cross-sectional areas ABE
= 11,100 mm2 and ACF = 9,280 mm2. The distances between various
points on the bars are shown in the figure.
Determine the vertical displacements δA and δD of points A and D,
respectively.
and this is the part of solution
Just what I want to know is how to draw
displacement diagram
δ(BE) is 0.4mm, δ(CF) is 0.6mm but i don't know
why δ(A) ->δ(BE)->δ(CF)-> δ(D) is linearly
increase and δ(A) is smaller than δ(D)
1.5 m - 1.5 m-a 2.1 m — m A B ID P1 = 400 KN 2.4 m P2 = 360 KN = F 0.6 m E PROBLEM 2.2-18
Compute the elongation in bar CF FCFLCF SCF = EACF (464x10²)(2.4) (200x10(9280x10) =6x104 m = 0.6 mm - Draw the displacement diagram as follows: A 1.5m B 1.5m c 2.1m D 8. SBE SCE Sp
The horizontal rigid beam ABCD is supported by vertical bars BE and CF and is loaded by vertical forces P1 = 400 kN and
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