Assuming 100% yield, how many mL of acetic acid (MW = 60.05 g/mol, density = 1.05 g/mL) would need to be used to prepare

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answerhappygod
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Assuming 100% yield, how many mL of acetic acid (MW = 60.05 g/mol, density = 1.05 g/mL) would need to be used to prepare

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Assuming 100% yield, how many mL of acetic acid (MW = 60.05 g/mol, density = 1.05 g/mL) would need to be used to prepare 0.60 mol of n-propyl acetate (MW = 102.13 g/mol, density = 0.89 g/mL, pear-scented
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