- The Reaction Of Peroxydisulfate Ion S O82 With Iodide Ion 1 Is S 08 Aq 31 Aq 2so4 Aq 13 Aq From This Da 1 (42.83 KiB) Viewed 37 times
The reaction of peroxydisulfate ion (S₂O82) with iodide ion (1) is S₂08² (aq) +31 (aq) →2SO4 (aq) + 13 (aq) From this da
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The reaction of peroxydisulfate ion (S₂O82) with iodide ion (1) is S₂08² (aq) +31 (aq) →2SO4 (aq) + 13 (aq) From this da
The reaction of peroxydisulfate ion (S₂O82) with iodide ion (1) is S₂08² (aq) +31 (aq) →2SO4 (aq) + 13 (aq) From this data collected at a certain temperature, calculate the rate constant. k= Exp. 1 2 3 Ms [$₂08²] [] (M) (M) 0.0800 0.0800 Initial Rate (M/s) 0.0340 2.90 x 10-4 0.0170 1.45 x 10-4 0.0170 2.90 x 104 0.160