What Is The Ha In Mol L Of A Solution Containing 1 49 Mol L Of A Diprotic Acid With Pka1 3 06 And Pkaz 9 12 1 (16.14 KiB) Viewed 22 times
What Is The Ha In Mol L Of A Solution Containing 1 49 Mol L Of A Diprotic Acid With Pka1 3 06 And Pkaz 9 12 2 (16.14 KiB) Viewed 22 times
What is the [HA] (in mol L-¹) of a solution containing 1.49 mol L-¹ of a diprotic acid with pKA1 = 3.06 and pkAz = 9.12? Answer: H₂A + H₂O HA+H₂O H₂O + HA PKA1 H₂O + A² PKA2
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