1 2 3 Ph 0 4 X 5 6 7 8 An Analytical Chemist Is Titrating 234 1 Ml Of A 0 4900m Solution Of Aniline Ch Nh With 1 (93.76 KiB) Viewed 37 times
✓ 1 2 3 pH = 0 4 X 5 6 ? 7 8 An analytical chemist is titrating 234.1 mL of a 0.4900M solution of aniline (CH²NH₂) with a 0.4800M solution of HNO3. The pK, of aniline is 9.37. Calculate the pH of the base solution after the chemist has added 269.8 mL of the HNO3 solution to it. 9 Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places. ✓ 10
Titration & Lewis Question 2 of 10 (1 point) | Question Attempt: 1 of Unlimited ✓ 1 acid A B 2 с Ка 0 ✓ 3 6.58 x 10 Complete the following table, which lists information about the measured acid dissociation constants of three unknown v acids. Note: be sure each number you put in the table has the correct number of significant digits. -4 pKa 2.50 0 4 3.8 5 relative strength (Choose one) ✓ (Choose one) ✓ 6 (Choose one) ✓ 7 x10 8 9 ✓ 10
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