Consider the reaction. 2Pb(s)+O2(g)⟶2PbO(s) An excess of oxygen reacts with 451.4 g of lead, forming 358.2 g of lead(II)

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answerhappygod
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Consider the reaction. 2Pb(s)+O2(g)⟶2PbO(s) An excess of oxygen reacts with 451.4 g of lead, forming 358.2 g of lead(II)

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Consider the reaction.
2Pb(s)+O2(g)⟶2PbO(s)
An excess of oxygen reacts with 451.4 g of lead,forming 358.2 g of lead(II) oxide. Calculate thepercent yield of the reaction.
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