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Answer Happy • The equilibrium constant for the following reaction is 1.0 x 10²3 Cr³+ (aq) + H₂EDTA² (aq) CrEDTA (aq) + 2H (aq) 0₂C-CH₂
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The equilibrium constant for the following reaction is 1.0 x 10²3 Cr³+ (aq) + H₂EDTA² (aq) CrEDTA (aq) + 2H (aq) 0₂C-CH₂

Posted: Mon Jul 11, 2022 1:45 pm
by answerhappygod
The Equilibrium Constant For The Following Reaction Is 1 0 X 10 3 Cr Aq H Edta Aq Credta Aq 2h Aq 0 C Ch 1
The Equilibrium Constant For The Following Reaction Is 1 0 X 10 3 Cr Aq H Edta Aq Credta Aq 2h Aq 0 C Ch 1 (16.98 KiB) Viewed 33 times
The equilibrium constant for the following reaction is 1.0 x 10²3 Cr³+ (aq) + H₂EDTA² (aq) CrEDTA (aq) + 2H (aq) 0₂C-CH₂ O₂C-CH₂ EDTA- N-CH₂-CH₂-N CH, CO, CH, CO, Ethylenediaminetetraacetate EDTA is used as a complexing agent in chemical analysis. Solutions of EDTA, usually containing the disodium salt Na₂H₂ EDTA, are used to treat heavy meta poisoning. Calculate (Cr] at equilibrium in a solution originally 0.0020 M in Cr³+ and 0.030 M in H₂ EDTA and buffered at pH=6.00. Assume that H₂EDTA form dominates at this pH. [C]-[ M