The equilibrium constant for the following reaction is 1.0 x 10²3 Cr³+ (aq) + H₂EDTA² (aq) CrEDTA (aq) + 2H (aq) 0₂C-CH₂

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

The equilibrium constant for the following reaction is 1.0 x 10²3 Cr³+ (aq) + H₂EDTA² (aq) CrEDTA (aq) + 2H (aq) 0₂C-CH₂

Post by answerhappygod »

The Equilibrium Constant For The Following Reaction Is 1 0 X 10 3 Cr Aq H Edta Aq Credta Aq 2h Aq 0 C Ch 1
The Equilibrium Constant For The Following Reaction Is 1 0 X 10 3 Cr Aq H Edta Aq Credta Aq 2h Aq 0 C Ch 1 (16.98 KiB) Viewed 32 times
The equilibrium constant for the following reaction is 1.0 x 10²3 Cr³+ (aq) + H₂EDTA² (aq) CrEDTA (aq) + 2H (aq) 0₂C-CH₂ O₂C-CH₂ EDTA- N-CH₂-CH₂-N CH, CO, CH, CO, Ethylenediaminetetraacetate EDTA is used as a complexing agent in chemical analysis. Solutions of EDTA, usually containing the disodium salt Na₂H₂ EDTA, are used to treat heavy meta poisoning. Calculate (Cr] at equilibrium in a solution originally 0.0020 M in Cr³+ and 0.030 M in H₂ EDTA and buffered at pH=6.00. Assume that H₂EDTA form dominates at this pH. [C]-[ M
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Top
Post Reply

Return to “Archived Questions & Answers”