Question 8 (1 point) For the reaction below. 66.9 g CaCO3 is mixed with 99.6 g of XCI. How many grams of CO₂ will be pro
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Question 8 (1 point) For the reaction below. 66.9 g CaCO3 is mixed with 99.6 g of XCI. How many grams of CO₂ will be pro
Question 8 (1 point) For the reaction below. 66.9 g CaCO3 is mixed with 99.6 g of XCI. How many grams of CO₂ will be produced? CaCO3 (s) + 2 XCI (aq)--> CaCl₂ (aq) + CO₂(g) + X₂0 (1) You may not use all of the following molar mass information CaCO3 (s) = 100.09 g/mol XCI (aq) 59.0 g/mol CaCl₂ (aq) 110.98 g/mol U CO₂ (g) = 44.01 g/mol X₂0 (1)-98.12 g/mol Your answer should have 3 significant figures. Your Answer: Answer units