Given: (1) 2H2(g) + O2(g) -> 2H20(1) AH = -571.6 kJ (2) N205(g) + H20(1) -> 2HNO3(1) AH = -73.7 kJ (3) 1/2N2(g) +3/202(g

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Given 1 2h2 G O2 G 2h20 1 Ah 571 6 Kj 2 N205 G H20 1 2hno3 1 Ah 73 7 Kj 3 1 2n2 G 3 202 G 1 (60.16 KiB) Viewed 15 times

Given: (1) 2H2(g) + O2(g) -> 2H20(1) AH = -571.6 kJ (2) N205(g) + H20(1) -> 2HNO3(1) AH = -73.7 kJ (3) 1/2N2(g) +3/202(g) + 1/2H2(g) -> HNO3(1) ΔΗ = -174.1 kJ Calculate the AH(in kJ) for N2(g) + 5/202(g) N205(g) fill in blank Write answer in decimal form to three significant figures. No units in answer. Make sure to include the correct sign.