Given: SO₂Cl₂(g) = SO₂(g) + Cl₂(g) Kc = 119 at 298 K In this reaction at equilibrium, the concentration of SO₂Cl2 is 0.0
Posted: Mon Jul 11, 2022 1:23 pm
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Given: SO₂Cl₂(g) SO₂(g) + Cl₂(g) Kc = 119 at 298 K Given that this reaction starts with 0.2 M of the SO₂Cl2, what is the expression for K at equilibrium?
Given: SO₂Cl₂(g) SO₂(g) + Cl₂(g) Kc = 119 at 298 K Given that the reaction starts with 3 M of each of the products the SO2 and Cl₂, what is the concentration of the reactant, SO₂Cl₂(g), at equilibrium?