Given: SO₂Cl₂(g) = SO₂(g) + Cl₂(g) Kc = 119 at 298 K In this reaction at equilibrium, the concentration of SO₂Cl2 is 0.0

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answerhappygod
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Given: SO₂Cl₂(g) = SO₂(g) + Cl₂(g) Kc = 119 at 298 K In this reaction at equilibrium, the concentration of SO₂Cl2 is 0.0

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Given So Cl G So G Cl G Kc 119 At 298 K In This Reaction At Equilibrium The Concentration Of So Cl2 Is 0 0 1
Given So Cl G So G Cl G Kc 119 At 298 K In This Reaction At Equilibrium The Concentration Of So Cl2 Is 0 0 1 (13.24 KiB) Viewed 23 times
Given So Cl G So G Cl G Kc 119 At 298 K In This Reaction At Equilibrium The Concentration Of So Cl2 Is 0 0 2
Given So Cl G So G Cl G Kc 119 At 298 K In This Reaction At Equilibrium The Concentration Of So Cl2 Is 0 0 2 (11.17 KiB) Viewed 23 times
Given So Cl G So G Cl G Kc 119 At 298 K In This Reaction At Equilibrium The Concentration Of So Cl2 Is 0 0 3
Given So Cl G So G Cl G Kc 119 At 298 K In This Reaction At Equilibrium The Concentration Of So Cl2 Is 0 0 3 (13.71 KiB) Viewed 23 times
Given: SO₂Cl₂(g) = SO₂(g) + Cl₂(g) Kc = 119 at 298 K In this reaction at equilibrium, the concentration of SO₂Cl2 is 0.01 M and SO2 is 1.50 M. What is the concentration of Cl₂?
Given: SO₂Cl₂(g) SO₂(g) + Cl₂(g) Kc = 119 at 298 K Given that this reaction starts with 0.2 M of the SO₂Cl2, what is the expression for K at equilibrium?
Given: SO₂Cl₂(g) SO₂(g) + Cl₂(g) Kc = 119 at 298 K Given that the reaction starts with 3 M of each of the products the SO2 and Cl₂, what is the concentration of the reactant, SO₂Cl₂(g), at equilibrium?
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