- Given The Two Reactions 3 Pbcl2 Aq Pb2 Aq 2cl Aq K3 1 78x10 10 And 4 Agcl Aq Ag Aq Cl Aq K4 1 17 1 (37.91 KiB) Viewed 18 times
Given the two reactions 3. PbCl2 (aq) = Pb2+ (aq) + 2Cl(aq), K3=1.78x10-10, and 4. AgCl(aq) Ag+ (aq) + Cl(aq), K4 = 1.17
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Given the two reactions 3. PbCl2 (aq) = Pb2+ (aq) + 2Cl(aq), K3=1.78x10-10, and 4. AgCl(aq) Ag+ (aq) + Cl(aq), K4 = 1.17
Given the two reactions 3. PbCl2 (aq) = Pb2+ (aq) + 2Cl(aq), K3=1.78x10-10, and 4. AgCl(aq) Ag+ (aq) + Cl(aq), K4 = 1.17x10-4, what is the equilibrium constant Kfinal for the following reaction? Express your answer numerically. ► View Available Hint(s) Kfinal = PbCl2 (aq) + 2Ag+ (aq) = 2AgCl(aq) + Pb²+ (aq) VE ΑΣΦ → S ?