- 20 The Equilibrium Constant At 900 K For The Reaction Below Is Given N2 G 3 2 H O G Nh3 G O G Kc 1 (16.99 KiB) Viewed 24 times
20. The equilibrium constant at 900 K for the reaction below is given: ½ N2 (g) + 3/2 H₂O (g) + NH3 (g) + % O₂ (g) Kc =
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20. The equilibrium constant at 900 K for the reaction below is given: ½ N2 (g) + 3/2 H₂O (g) + NH3 (g) + % O₂ (g) Kc =
20. The equilibrium constant at 900 K for the reaction below is given: ½ N2 (g) + 3/2 H₂O (g) + NH3 (g) + % O₂ (g) Kc = 1.97 x 10-20 Calculate Ke at 900 K for the following reaction using the information above: 4 NH3 (g) + 3 O2 (g) + 2 N₂ (g) + 6 H₂O (g)