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Question 16 (10 points) What volume of water vapor would be produced from the combustion of 554.11 grams of propane (C3H
Posted: Mon Jul 11, 2022 1:20 pm
by answerhappygod
- Question 16 10 Points What Volume Of Water Vapor Would Be Produced From The Combustion Of 554 11 Grams Of Propane C3h 1 (25.53 KiB) Viewed 21 times
Question 16 (10 points) What volume of water vapor would be produced from the combustion of 554.11 grams of propane (C3Hg) with 1,614.79 grams of oxygen gas, under a pressure of 0.95 atm and a temperature of 350. degrees C? Given: C3H8(g) + 5 O2(g) ---> 3 CO₂(g) + 4H₂O(g) (OR C3 Hg ("g") + 5 0₂ ("g") right arrow 3 C O₂ ("g") + 4 H₂O ("g") R = 0.08206- L atm mol K Do not type units with your answer Your Answer: Answer