Question 16 (10 points) What volume of water vapor would be produced from the combustion of 554.11 grams of propane (C3H
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Question 16 (10 points) What volume of water vapor would be produced from the combustion of 554.11 grams of propane (C3H
Question 16 (10 points) What volume of water vapor would be produced from the combustion of 554.11 grams of propane (C3Hg) with 1,614.79 grams of oxygen gas, under a pressure of 0.95 atm and a temperature of 350. degrees C? Given: C3H8(g) + 5 O2(g) ---> 3 CO₂(g) + 4H₂O(g) (OR C3 Hg ("g") + 5 0₂ ("g") right arrow 3 C O₂ ("g") + 4 H₂O ("g") R = 0.08206- L atm mol K Do not type units with your answer Your Answer: Answer