- What Is The Ha In Mol L Of A Solution Containing 1 459 Mol L 1 Of A Diprotic Acid With Pka1 3 36 And Pka2 8 0 1 (20.2 KiB) Viewed 27 times
What is the [HA-] (in mol L-¹) of a solution containing 1.459 mol L-1 of a diprotic acid with PKA1 = 3.36 and PKA2 = 8.0
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What is the [HA-] (in mol L-¹) of a solution containing 1.459 mol L-1 of a diprotic acid with PKA1 = 3.36 and PKA2 = 8.0
What is the [HA-] (in mol L-¹) of a solution containing 1.459 mol L-1 of a diprotic acid with PKA1 = 3.36 and PKA2 = 8.04 ? H₂A + H₂O H3O+ + HA HA + H₂O = H3O+ + A²- pkA1 pkA2