1. What weight of 98.5% KHC8H404 is equivalent to 35ml, 0.01N NaOH? 2. What volume of 0.1M Ba(OH)2 is needed to titrate

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1 What Weight Of 98 5 Khc8h404 Is Equivalent To 35ml 0 01n Naoh 2 What Volume Of 0 1m Ba Oh 2 Is Needed To Titrate 1 (167.73 KiB) Viewed 27 times

1. What weight of 98.5% KHC8H404 is equivalent to 35ml, 0.01N NaOH? 2. What volume of 0.1M Ba(OH)2 is needed to titrate 1.35g of 98.5% KHC8H404? 3. 3. 25 ml of HCI was required to neutralize 28.6 ml of NaOH. The acid solution was standardize using 1.2654 g of sodium carbonate requiring 30.2 ml to reach the salmon pink endpoint. Afterwards, these solutions were used in the assay of zinc oxide. The following data were collected: Weight of ZnO sample used: 1.25 g Volume of sodium hydroxide: 23.1 ml, Volume of hydrochloric acid: 50 ml → Complete the results: N of HCl, N of NaOH, meg of analyte, Wt of pure analyte, % pure analyte