Question 6 Suppose that the curve whose parametric equations are =t, y = 5t, 0≤t≤ 2 is rotated around the x-axis. Find t

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Question 6 Suppose that the curve whose parametric equations are =t, y = 5t, 0≤t≤ 2 is rotated around the x-axis. Find t

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Question 6 Suppose That The Curve Whose Parametric Equations Are T Y 5t 0 T 2 Is Rotated Around The X Axis Find T 1
Question 6 Suppose That The Curve Whose Parametric Equations Are T Y 5t 0 T 2 Is Rotated Around The X Axis Find T 1 (28.64 KiB) Viewed 33 times
Question 6 Suppose That The Curve Whose Parametric Equations Are T Y 5t 0 T 2 Is Rotated Around The X Axis Find T 2
Question 6 Suppose That The Curve Whose Parametric Equations Are T Y 5t 0 T 2 Is Rotated Around The X Axis Find T 2 (33.32 KiB) Viewed 33 times
Question 6 Suppose That The Curve Whose Parametric Equations Are T Y 5t 0 T 2 Is Rotated Around The X Axis Find T 3
Question 6 Suppose That The Curve Whose Parametric Equations Are T Y 5t 0 T 2 Is Rotated Around The X Axis Find T 3 (36.54 KiB) Viewed 33 times
Question 6 Suppose That The Curve Whose Parametric Equations Are T Y 5t 0 T 2 Is Rotated Around The X Axis Find T 4
Question 6 Suppose That The Curve Whose Parametric Equations Are T Y 5t 0 T 2 Is Rotated Around The X Axis Find T 4 (34.9 KiB) Viewed 33 times
Question 6 Suppose that the curve whose parametric equations are =t, y = 5t, 0≤t≤ 2 is rotated around the x-axis. Find the exact area of the resulting surface. О 10,6 20√26T 2 pts O√26T O26T
Question 7 1 pts Suppose that the curve whose parametric equations are x = 3t², y = 2t³, 0≤t≤ 5 is rotated around the y-axis. Find an integral that represents the exact area of the resulting surface. O 24π fot√1+t² dt O 36π fo t³√1+t²dt Of 6t√1+t²dt O 12π fot²√1+t²dt
Question 8 Which one of the following integrals is to determine the surface area by revolving x = √t, y = lnt, 0≤t≤ 1 about the y-axis. Of 2nlnt +/dt So 2√√√1+/dt So vt O O √dt 1 pts So 2√√+ dt 2π /
> Question 9 The curve C is given parametrically by a = 1+ 3t², y = 4+2+³. Find the arc length of the curve within the interval of 0 ≤ t ≤ 1. 02 (2√2+1) 02 (2√2-1) 02 (√2-1) 02 (√2+1) 2 pts
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