A certain computer algorithm executes twice as many operations when it is run with an input of size k as when it is run

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A certain computer algorithm executes twice as many operationswhen it is run with an input of size k as when it is run with aninput of size k − 1 (where k is an integer that is greater than 1).When the algorithm is run with an input of size 1, it executesseven operations. How many operations does it execute when it isrun with an input of size 26? For each integer n ≥ 1, let sn − 1 bethe number of operations the algorithm executes when it is run withan input of size n. Then s0 = and sk = for each integer k ≥ 1.Therefore, s0, s1, s2, is ---Select--- with constant ---Select--- ,which is . So, for every integer n ≥ 0, sn = . It follows that foran input of size 26, the number of operations executed by thealgorithm is s ---Select--- , which equals

A Certain Computer Algorithm Executes Twice As Many Operations When It Is Run With An Input Of Size K As When It Is Run 1 (58.78 KiB) Viewed 30 times

A certain computer algorithm executes twice as many operations when it is run with an input of size k as when it is run with an input of size k - 1 (where k is an integer that is greater than 1). When the algorithm is run with an input of size 1, it executes seven operations. How many operations does it execute when it is run with an input of size 26? For each integer n ≥ 1, let s₁ - 1 be the number of operations the algorithm executes when it is run with an input of size n. Then for each integer k ≥ 1. Therefore, S0, S₁, S₂, is ---Select--- with and Sk So = constant ---Select--- = " which is So, for every integer n ≥ 0, sn = input of size 26, the number of operations executed by the algorithm is s --Select--- which equals . It follows that for an