Using Equation (4.2.7), compute the sagged equilibrium position u(x) if Q(x, t) = -g. The boundary conditions are u(O) =

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Using Equation (4.2.7), compute the sagged equilibrium position u(x) if Q(x, t) = -g. The boundary conditions are u(O) =

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Using Equation 4 2 7 Compute The Sagged Equilibrium Position U X If Q X T G The Boundary Conditions Are U O 1
Using Equation 4 2 7 Compute The Sagged Equilibrium Position U X If Q X T G The Boundary Conditions Are U O 1 (246.16 KiB) Viewed 55 times
Using Equation (4.2.7), compute the sagged equilibrium position u(x) if Q(x, t) = -g. The boundary conditions are u(O) = 0 and u(L) = 0. d'u O=8P(x) d'u_g ex² To = = * Po(x) Integrating on both sides gives, dug = 5 */ Po(s) ds + C₁ dx To Again, integrating on both sides gives, u₂(x)=₁/P₁ (2) dz+c₁ ds + C₂ c = S" ( √° ½ Po (=) dz]}ds + ["*¢‚ds + c₂ = £ £ ( √* Po ( ² ) α= }ds + ₂x + €₂ Therefore, (x) = & S" ("* P₁ (²) d=) ds + ₁₂x + c₂ 2 (2) What does z represent? What does s represent? Since c1 is inside the double integral how can we just pull it out and now its in one integral?
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