Construction 3: To bisect a given angle Given: Z A To construct: The bisector of ZA Construction: With A as center and a

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Construction 3: To bisect a given angle Given: Z A To construct: The bisector of ZA Construction: With A as center and a

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Construction 3 To Bisect A Given Angle Given Z A To Construct The Bisector Of Za Construction With A As Center And A 1
Construction 3 To Bisect A Given Angle Given Z A To Construct The Bisector Of Za Construction With A As Center And A 1 (68.68 KiB) Viewed 36 times
Construction 3: To bisect a given angle Given: Z A To construct: The bisector of ZA Construction: With A as center and a convenient radius, construct an arc intersecting the sides of Z A at B and C. With B and C as center and equal radii, construct arcs intersecting in D. Draw AD. Then AD is the required bisector. (A ABDA ADC by s.s.s.s.s.s.; hence 2 1 22.) Explanation: AD is the required angle bisector since A ABD = A ADC by s.s.s. and 21 22 by cpctc,
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