17. Banner Mattress and Furniture Company wishes to study the number of credit applications received per day for the las

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17. Banner Mattress and Furniture Company wishes to studythe number of credit applications received per day for the last 395days.The sample information is reported below.
To interpret, there were 10 days on which no credit applicationswere received, 26 days on which only one application was received,and so on. Would it be reasonable to conclude that the populationdistribution is Poisson with a mean of 4.0? Use the 0.1significance level. Hint: To find the expectedfrequencies use the Poisson distribution with a mean of 4.0. Findthe probability of exactly one success given a Poisson distributionwith a mean of 4.0. Multiply this probability by 395 to find theexpected frequency for the number of days in which there wasexactly one application. Determine the expected frequency for theother days in a similar manner.H0: Distribution with Poissonwith µ = 4.H1: Distribution is not Poissonwith µ = 4.

17 Banner Mattress And Furniture Company Wishes To Study The Number Of Credit Applications Received Per Day For The Las 1 (16.67 KiB) Viewed 31 times

17 Banner Mattress And Furniture Company Wishes To Study The Number Of Credit Applications Received Per Day For The Las 2 (5.58 KiB) Viewed 31 times

a. State the decision rule. Use 0.1 significance level. (Round your answer to 3 decimal places.) If chi-square > b. Compute the value of chi-square. (Round foto 4 decimal places. Round (fo-f²/f to 4 decimal places. Round x² to 4 decimal places.) Applications fo 0 1 2 3 4 5 or more Total reject Ho fe (fo-fe)²/fe

c. What is your decision regarding H₂? Ho. There sufficient evidence to reject the null that the distribution is Poisson with μ = 4.