Could someone please tell me how to evaluate limn→inf[sin(2/n^2)+sin(4/n^2)+sin(6/n^2)+...+sin(2n/n^2)]?
Posted: Mon Jul 11, 2022 11:10 am
Could someone please tell me how to evaluatelimn→inf[sin(2/n^2)+sin(4/n^2)+sin(6/n^2)+...+sin(2n/n^2)]?