Could someone please tell me how to evaluate limn→inf[sin(2/n^2)+sin(4/n^2)+sin(6/n^2)+...+sin(2n/n^2)]?

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answerhappygod
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Could someone please tell me how to evaluate limn→inf[sin(2/n^2)+sin(4/n^2)+sin(6/n^2)+...+sin(2n/n^2)]?

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Could someone please tell me how to evaluatelimn→inf[sin(2/n^2)+sin(4/n^2)+sin(6/n^2)+...+sin(2n/n^2)]?
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