EXAMPLE nt (2, 2). (a) Set up the integral for the length of the arc of the hyperbola xy = 5 from the point (1, 5) to th

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EXAMPLE nt (2, 2). (a) Set up the integral for the length of the arc of the hyperbola xy = 5 from the point (1, 5) to th

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Example Nt 2 2 A Set Up The Integral For The Length Of The Arc Of The Hyperbola Xy 5 From The Point 1 5 To Th 1
Example Nt 2 2 A Set Up The Integral For The Length Of The Arc Of The Hyperbola Xy 5 From The Point 1 5 To Th 1 (35.8 KiB) Viewed 27 times
EXAMPLE nt (2, 2). (a) Set up the integral for the length of the arc of the hyperbola xy = 5 from the point (1, 5) to the point ( (b) Use Simpson's Rule with n = 10 to estimate the arc length. SOLUTION (a) We have dy dx L= and so the arc length dy' dx 10/2 + 25 = 2.5677 dx √x + 25 dx. (b) Using Simpson's Rule with a 1, b = 2, n = 10, Ax= 0.1, and f(x) = 1 - 1² √² + 25 d L- dx AX (1) + 4f(1.1) + 2(1.2) + 4f(1.3) ++2f(1.8) + 4f(1.9) + f(2)] 3 x (rounded to four decimal places). +1 , we have
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